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servlet读取数据库数据 输出为XML时的乱码问题：

恩 首先:你的out对象是先获取的 获取完之后你才设置的字符集，矛盾

你先吧response设置好之后 在进行写入操作

所以要在PrintWriter out = response.getWriter();之前进行字符的设置工作

response.setContentType("text/xml; charset=gb2312");//先设置字符集 然后再取值  response.setHeader("Cache-Control", "no-cache");//顺序放后就会出现错误

PrintWriter out = response.getWriter();  String className, url, uid, pwd;

className = "com.microsoft.jdbc.sqlserver.SQLServerDriver";

url = "jdbc:microsoft:sqlserver://127.0.0.1:1433;DatabaseName=text";

uid = "sa";

pwd = "sa";

int l;

try {

Class.forName(className);

} catch (ClassNotFoundException e) {

e.printStackTrace();

}

try {

Connection cn = DriverManager.getConnection(url, uid, pwd);

Statement sql = cn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE,

ResultSet.CONCUR_READ_ONLY);

ResultSet rs = sql.executeQuery("SELECT yg_name,yg_id FROM yg");

rs.last();

l = rs.getRow();

rs.beforeFirst();

// 设置输出信息的格式及字符集

out.println("<?xml version=\"1.0\" encoding=\"utf-8\"?>");

out.println("");

while (rs.next()) {

out.println("" + l + "");

System.out.println("" + rs.getString("yg_name") + "");

out.println("" + rs.getString("yg_name") + "");

out.println("" + rs.getString("yg_name") + "");

out.println("" + rs.getString("yg_id") + "");

}

out.println("");

rs.close();

cn.close();

} catch (Exception el) {

el.printStackTrace();

}

}

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2010-03-19 15:50

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