化纤公司网站建设/网页设计用什么软件

code 1

可以先借助度娘寻求一张菱形块的图片哦！嗯哼----来咯！

接下来呢，就要自个数数了，哈哈，数一下对应的 * 号以及它前边空格的位数，寻找相应的规律然后进行代码计算，其中 i 表示对应的行，j 表示对应的列

void Show(int n)
{// 菱形的上半部分
int i = 0;for (; i < n; i++) {int j = 0;for (; j < n - 1 - i; j++) {printf(" ");}for (j = 0; j < 2 * i + 1; j++) {printf("*");}printf("\n");}// 对应的下半部分for (i = 0; i < n - 1; i++) {int j = 0;for (; j <= i; j++) {printf(" ");}for (j = 0; j < 2 * n - 3 - 2 * i ; j++) {printf("*");}printf("\n");}}int main()
{                     //函数的调用Show(6);
}

这种方法其实是比较麻烦的，相信正在看的你也这么认为的叭！
其实，这个代码不是我的终极目的，，哈哈

code 2

不通过计算 * 和空格的个数，我们直接打印可不？当然可以咯，看-------->

#include <stdio.h>
#include<windows.h>int main()
{char graph[100][100] = {"        *","       ***","     *******","    *********","     *******","       ***","        *",};int i = 0;for (; i < 7; i++) {              // i 表示行数printf("%s\n", graph[i]);}system("pause");return 0;
}

code 3

最后附上一张小白独创（其实也不算是独创吧，也就是稍微举一反三了一下下）

#include<stdio.h>
#include<window.h>int main()
{char a[1000][1000] = {"                                                          ","                                                          ","                                                          ","                                                          ","            ***********                ***********","        ***             *            *             ***","    ***                   *        *                  ***","       ***                  *    *                 ***","          ***                 *                 ***","             ***                             ***","                ***                       ***","                   ***                 ***","                      ***          ***","                         ***    ***","                            ****","                              *","                                                          ","                                                          ","                                                          ",};
int i = 0;for (; i < 18; i++) {printf("%s\n", a[i]);}printf("\n");system("pause");return 0;
}

(空间有限，可能有些乱码…不过仿照之前菱形块的输出，新手的同伴应该可以自己打出来)