网站开发工程师能在家工作吗/自己怎么优化网站排名
由于您的数据未排序，请使用^{} object来具体化新键的列表，然后按胶片标题键：from collections import defaultdict
grouped = defaultdict(list)
for film in f:
grouped[film['film'][0]].append(film)
{cd2>值是用来分组的。如果要使用更复杂的标题分组，则必须创建该密钥的规范版本。在
演示：
^{pr2}$
使用SoundEx对胶片进行分组非常简单：from itertools import groupby, islice, ifilter
_codes = ('bfpv', 'cgjkqsxz', 'dt', 'l', 'mn', 'r')
_sounds = {c: str(i) for i, code in enumerate(_codes, 1) for c in code}
_sounds.update(dict.fromkeys('aeiouy'))
def soundex(word, _sounds=_sounds):
grouped = groupby(_sounds[c] for c in word.lower() if c in _sounds)
if _sounds.get(word[0].lower()):
next(grouped) # remove first group.
sdx = ''.join([k for k, g in islice((g for g in grouped if g[0]), 3)])
return word[0].upper() + format(sdx, '<03')
grouped_by_soundex = defaultdict(list)
for film in f:
grouped_by_soundex[soundex(film['film'][0])].append(film)
导致：>>> pprint(dict(grouped_by_soundex))
{u'B436': [{u'director': [u'Ridley Scott'],
u'film': [u'Blade Runner'],
u'price': [u'19,99'],
u'year': [u'1982']}],
u'K414': [{u'director': [u'Tarantino'],
u'film': [u'Kill Bill vol.1'],
u'price': [u'10,00'],
u'year': [u'2003']}],
u'P412': [{u'director': [u'Tarantino'],
u'film': [u'Pulp Fiction'],
u'price': [u'20,00'],
u'year': [u'1994']},
{u'director': [u'Tarantino'],
u'film': [u'Pulp Fyction'],
u'price': [u'15,00'],
u'year': [u'1994']}],
u'S363': [{u'director': [u'E. de Souza'],
u'film': [u'Street Fighter'],
u'price': [u'2,00'],
u'year': [u'1994']}],
u'T536': [{u'director': [u'Wachowski'],
u'film': [u'The Matrix'],
u'price': [u'19,00'],
u'year': [u'1999']},
{u'director': [u'Wachowski'],
u'film': [u'The Matrix Reloaded'],
u'price': [u'9,99'],
u'year': [u'2003']},
{u'director': [u'Wachowski'],
u'film': [u'The Matrix'],
u'price': [u'20,00'],
u'year': [u'1999']}]}