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问题描述:
无线电台的RS制信号报告是由三两个部分组成的:
R(Readability) 信号可辨度即清晰度.
S(Strength) 信号强度即大小.
其中R位于报告第一位,共分5级,用1—5数字表示.
1---Unreadable
2---Barely readable, occasional words distinguishable
3---Readable with considerable difficulty
4---Readable with practically no difficulty
5---Perfectly readable
报告第二位是S,共分九个级别,用1—9中的一位数字表示
1---Faint signals, barely perceptible
2---Very weak signals
3---Weak signals
4---Fair signals
5---Fairly good signals
6---Good signals
7---Moderately strong signals
8---Strong signals
9---Extremely strong signals
现在,你的程序要读入一个信号报告的数字,然后输出对应的含义。如读到59,则输出:
Extremely strong signals, perfectly readable.
输入格式:
一个整数,信号报告。整数的十位部分表示可辨度,个位部分表示强度。输入的整数范围是[11,59]内有效的数字,这个范围外的数字不可能出现在测试数据中。
输出格式:
一句话,表示这个信号报告的意义。按照题目中的文字,先输出表示强度的文字,跟上逗号和空格,然后是表示可辨度的文字,跟上句号。注意可辨度的句子的第一个字母是小写的。注意这里的标点符号都是英文的。
输入样例:
33
输出样例:
Weak signals, readable with considerable difficulty.
时间限制:500ms内存限制:32000kb
问题分析:
对switch循环的简单运用
代码实现:
importjava.util.Scanner;public classMain
{public static voidmain(String[] args)
{
Scanner in=newScanner(System.in);inti;intfirst;intsecond;
i=in.nextInt();
second=i/10;//十位数
first=i%10;//个位数if(i>=11&&i<=59) {switch(first) //个位数决定第一句话
{case 1:
System.out.print("Faint signals, barely perceptible,");break;case 2:
System.out.print("Very weak signals,");break;case 3:
System.out.print("Weak signals,");break;case 4:
System.out.print("Fair signals,");break;case 5:
System.out.print("Fairly good signals,");break;case 6:
System.out.print("Good signals,");break;case 7:
System.out.print("Moderately strong signals,");break;case 8:
System.out.print("Strong signals,");break;case 9:
System.out.print("Extremely strong signals,");break;
}switch(second) //十位数决定第二句话
{case 1:
System.out.print("Unreadable.");break;case 2:
System.out.print("Barely readable, occasional words distinguishable.");break;case 3:
System.out.print("Readable with considerable difficulty.");break;case 4:
System.out.print("Readable with practically no difficulty.");break;case 5:
System.out.print("Perfectly readable.");break;
}
}else{
System.out.println("输入数字错误!");
}
in.close();
}
}