网站建设营销一站式服务/营销策略案例
c语言函数指针的定义形式:返回类型 (*函数指针名称)(参数类型,参数类型,参数类型,…);
c++函数指针的定义形式:返回类型 (类名称::*函数成员名称)(参数类型,参数类型,参数类型,….);
以下代码编译环境:codeblocks with gcc in win 7
#include <stdio.h> #include <stdlib.h>int fun1() {printf("this is fun1 call\n");return 1; }void fun2(int k, char c) {printf("this is fun2 call:%d %c\n", k, c); }int main() {int (*pfun1)() = NULL;void (*pfun2)(int, char) = NULL;int a,b;pfun1 = fun1; //第一种赋值方法a = pfun1(); //第一种调用方法(推荐)printf("%d\n",a);b = (*pfun1)();//第二种调用方法printf("%d\n",b);pfun2 = &fun2;//第二种赋值方法(推荐,因为和其他数据指针赋值方法一致)pfun2(1,'a');(*pfun2)(2,'b');return 0; }
#include <iostream> using namespace std;class test { public:test(){cout<<"constructor"<<endl;}int fun1(int a, char c){cout<<"this is fun1 call:"<<a<<" "<<c<<endl;return a;}void fun2(double d)const{cout<<"this is fun2 call:"<<d<<endl;}static double fun3(char buf[]){cout<<"this is fun3 call:"<<buf<<endl;return 3.14;} };int main() {// 类的静态成员函数指针和c的指针的用法相同double (*pstatic)(char buf[]) = NULL;//不需要加类名pstatic = test::fun3; //可以不加取地址符号pstatic("myclaa");pstatic = &test::fun3;(*pstatic)("xyz");//普通成员函数int (test::*pfun)(int, char) = NULL; //一定要加类名pfun = &test::fun1; //一定要加取地址符号 test mytest;(mytest.*pfun)(1, 'a'); //调用是一定要加类的对象名和*符号//const 函数(基本普通成员函数相同)void (test::*pconst)(double)const = NULL; //一定要加constpconst = &test::fun2;test mytest2;(mytest2.*pconst)(3.33);// //构造函数或者析构函数的指针,貌似不可以,不知道c++标准有没有规定不能有指向这两者的函数指针 // (test::*pcon)() = NULL; // pcon = &test.test; // test mytest3; // (mytest3.*pcon)();return 0; }
#include <stdio.h> #include <stdlib.h>void fun(int k, char c) {printf("this is fun2 call:%d %c\n", k, c); }void fun1(void (*pfun)(int, char), int a, char c) {pfun(a, c); }int main() {fun1(fun, 1, 'a');return 0; } // c++ 的形式差不多
// c 形式 #include <stdio.h> #include <stdlib.h>void fun(int k, char c) {printf("this is fun2 call:%d %c\n", k, c); }//fun1 函数的参数为double,返回值为函数指针void(*)(int, char) void (*fun1(double d))(int, char) {printf("%f\n",d);return fun; }int main() {void (*p)(int, char) = fun1(3.33);p(1, 'a');return 0; }
//c++ 形式 #include <iostream> using namespace std;class test { public:int fun(int a, char c){cout<<"this is fun call:"<<a<<" "<<c<<endl;return a;} };class test2 {public:// test2 的成员函数fun1,参数是double,//返回值是test的成员函数指针int(test::*)(int, char)int (test::*fun1(double d))(int, char){cout<<d<<endl;return &test::fun;} };int main() {test mytest;test2 mytest2;int (test::*p)(int, char) = mytest2.fun1(3.33);(mytest.*p)(1, 'a');return 0; }
#include <stdio.h> #include <stdlib.h>float add(float a,float b){return a+b;} float minu(float a,float b){return a-b;}int main() {//定义一个函数指针数组,大小为2//里面存放float (*)(float, float)类型的指针float (*pfunArry[2])(float, float) = {&add, &minu};double k = pfunArry[0](3.33,2.22);// 调用printf("%f\n", k);k = pfunArry[1](3.33,2.22);printf("%f\n", k);return 0; } //c++ 可类比
#include <stdio.h> #include <stdlib.h>float add(float a,float b) {printf("%f\n",a+b);return a+b; } float minu(float a,float b) {printf("%f\n",a-b);return a-b; }//用pfunType 来表示float(*)(float, float) typedef float(*pfunType)(float, float);int main() {pfunType p = &add;//定义函数指针变量p(3.33, 2.22);pfunType parry[2] = {&add, &minu};//定义函数指针数组parry[1](3.33, 2.22);//函数指针作为参数可以定义为:void fun(pfunType p)//函数指针作为返回值可以定义为:pfunType fun();return 0; } //c++ 可类比
转自:http://www.cnblogs.com/TenosDoIt/p/3164081.html