题目如下：
解题思路：首先把路径以'/'分割成数组，接下来遍历数组，遇到空或者'.'直接删除，遇到'..'删除本身和前一个元素。
代码如下：
class Solution(object):def simplifyPath(self, path):""":type path: str:rtype: str"""l = path.split('/')inx = 0#print lwhile inx < len(l) and inx >= 0:if l[inx] == '' or l[inx] == '.':del l[inx]elif l[inx] == '..':del l[inx]if inx - 1 >= 0:del l[inx-1]inx -= 1else:inx += 1res = '/'for i in l:res += ires += '/'if len(res) == 1:return resreturn res[:-1]