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商城微信网站开发,常用的网络营销平台有哪些,沃尔玛的网站建设,网站常识异常描述 Exception in thread “main” java.lang.IllegalArgumentException: Multiple entries with same key: 11 and 11 异常场景测试环境提测一个功能马上要验收完毕，突然提示下单失败，和测试各种解释与本次更新无关；但测试担心是本次…

异常描述

Exception in thread “main” java.lang.IllegalArgumentException: Multiple entries with same key: 1=1 and 1=1

异常场景

测试环境提测一个功能马上要验收完毕，突然提示下单失败，和测试各种解释与本次更新无关；但测试担心是本次更新的内容影响了整体流程拒绝发送验证报告；
查看日志发现，异常信息类似上面，Bean中的一个属性字段重复了，还是作为Map的Key值重复的，Map的Key值是Set，自动过滤重复数据，为何报错

异常模拟

// import com.google.common.base.Function;
// import com.google.common.collect.Maps;public static void main(String[] args) {List<Integer> integerList = Arrays.asList(1,2,3,4,5,1,2,3,4);Map<Integer, Integer> map = Maps.uniqueIndex(integerList, new Function<Integer, Integer>() {@Overridepublic Integer apply(Integer input) {return input.intValue();}});System.out.println(map);}

源码分析

   // 方法调用public static <K, V> ImmutableMap<K, V> uniqueIndex(Iterable<V> values, Function<? super V, K> keyFunction) {return uniqueIndex(values.iterator(), keyFunction);}// 将集合中的数据放入 TerminalEntry<K, V>[] entries; public static <K, V> ImmutableMap<K, V> uniqueIndex(Iterator<V> values, Function<? super V, K> keyFunction) {Preconditions.checkNotNull(keyFunction);// 初始化 TerminalEntry<K, V>[] entries; Builder builder = ImmutableMap.builder();while(values.hasNext()) {V value = values.next();builder.put(keyFunction.apply(value), value);}return builder.build();}// size 大于 1 进入 default 方法public ImmutableMap<K, V> build() {switch(this.size) {case 0:return ImmutableBiMap.of();case 1:return ImmutableBiMap.of(this.entries[0].getKey(), this.entries[0].getValue());default:return new RegularImmutableMap(this.size, this.entries);}}RegularImmutableMap(int size, TerminalEntry<?, ?>[] theEntries) {this.entries = this.createEntryArray(size);int tableSize = Hashing.closedTableSize(size, 1.2D);this.table = this.createEntryArray(tableSize);this.mask = tableSize - 1;for(int entryIndex = 0; entryIndex < size; ++entryIndex) {TerminalEntry<K, V> entry = theEntries[entryIndex];K key = entry.getKey();// 判断是否有重复数据的方法// 将每个KEY取hash值与数组长度-1 取余// 保证数组中每个下标的位置上都有数据// 如果对新的KEY值Hash后在数组的该下标位置取到数据// 代表该数据已经存在int tableIndex = Hashing.smear(key.hashCode()) & this.mask;ImmutableMapEntry<K, V> existing = this.table[tableIndex];ImmutableMapEntry<K, V> newEntry = existing == null ? entry : new RegularImmutableMap.NonTerminalMapEntry(entry, existing);this.table[tableIndex] = (ImmutableMapEntry)newEntry;this.entries[entryIndex] = (ImmutableMapEntry)newEntry;this.checkNoConflictInBucket(key, (ImmutableMapEntry)newEntry, existing);}}private void checkNoConflictInBucket(K key, ImmutableMapEntry<K, V> entry, ImmutableMapEntry<K, V> bucketHead) {// 当已存在数据不空时调用此方法while(bucketHead != null) {checkNoConflict(!key.equals(bucketHead.getKey()), "key", entry, bucketHead);bucketHead = bucketHead.getNextInKeyBucket();}}// 抛出相应异常static void checkNoConflict(boolean safe, String conflictDescription, Entry<?, ?> entry1, Entry<?, ?> entry2) {if (!safe) {String var4 = String.valueOf(String.valueOf(conflictDescription));String var5 = String.valueOf(String.valueOf(entry1));String var6 = String.valueOf(String.valueOf(entry2));throw new IllegalArgumentException((new StringBuilder(34 + var4.length() + var5.length() + var6.length())).append("Multiple entries with same ").append(var4).append(": ").append(var5).append(" and ").append(var6).toString());}}