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提前致谢..
首先,我要这个用于android.
我必须发送一个带有zip文件的http发布请求,该zip文件包含一个包含名称列表的xml文件.
现在,根据我发送的名称列表,服务器将向我发送一个zip文件的二进制数据,我必须将该二进制数据(响应)另存为一个zip文件.
问题是,当我将此二进制数据另存为zip文件时,则无法提取该zip.
我认为这也可能是一些字符集问题.我需要将接收到的二进制数据转换为某些字符集,然后将其另存为zip.
请帮助我,我是android新手.任何执行此操作的ASYNC任务示例都将是很好的帮助.
这是我的代码.
private class sendMissingImagesToServer extends
AsyncTask {
@Override
protected byte[] doInBackground(String... params) {
String uri = params[0];
try {
MultipartEntityBuilder entity;
File f;
FileBody fb;
entity = MultipartEntityBuilder.create();
entity.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
f = new File(zipImageFile);
fb = new FileBody(f);
entity.addPart("orderFile", fb);
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(uri);
Log.e("Uploload Missing Image URL", "" + uri);
httppost.setEntity(entity.build());
HttpResponse response = httpclient.execute(httppost);
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer stringBuffer = new StringBuffer();
// byte[] fileBites=null;
String line = "";
while ((line = bufferedReader.readLine()) != null) {
stringBuffer.append(line);
}
bufferedReader.close();
// fileBites=stringBuffer.toString().getBytes();
// Log.e("FILE BITES", fileBites+"=>"+fileBites.length);
ByteArrayOutputStream bObj = new ByteArrayOutputStream();
bObj.reset();
bObj.write(stringBuffer.toString().getBytes());
return bObj.toByteArray();
// return stringBuffer.toString();
} catch (Exception e) {
return e.toString().getBytes();
}
}
@Override
protected void onPostExecute(byte[] result) {
// TODO Auto-generated method stub
super.onPostExecute(result);
Log.e("Response From Server", "" + result);
writeToFile(result);
}
}
@SuppressWarnings("resource")
private void writeToFile(byte[] data) {
try {
FileOutputStream fop = null;
File file;
file = new File(AppConstants.DataPath+"/products.zip");
fop = new FileOutputStream(file);
// if file doesnt exists, then create it
if (!file.exists()) {
file.createNewFile();
}
try {
fop.write(data);
} catch (IOException e) {
Log.e("Exception", "File write failed: " + e.toString());
}
unzipImage(AppConstants.DataPath + "/products.zip",
AppConstants.DataPath);
}catch (Exception E)
{
}
}